x^2+4x=252

Solution for x^2+4x=252 equation:

x^2+4x=252

We move all terms to the left:

x^2+4x-(252)=0

a = 1; b = 4; c = -252;
Δ = b2-4ac
Δ = 42-4·1·(-252)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-32}{2*1}=\frac{-36}{2}
=-18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+32}{2*1}=\frac{28}{2}
=14
$